Giải các phương trình sau:
1. $\sqrt{x+1}(3x^{2}+x+1)=x^{3}+3x^{2}+3x$
2. $2-\sqrt{\frac{x+2}{x-3}}=\sqrt{x+7}$
3. $2(x^{2}-3x+2)=3\sqrt{x^{3}+8}$
4. $4x^{2}-6x+1=\frac{-\sqrt{3}}{3}\sqrt{16x^{4}+4x^{2}+1}$
5. $3-x=\frac{2x^{2}-9x+17}{\sqrt{2x^{2}-6x+16}+\sqrt{3x-1}}$
6. $2(x-2)(\sqrt[3]{4x-4}+\sqrt{2x-2})=3x-1$
7. $\frac{x+2}{x+\sqrt{3x^{4}-11x^{2}+9}}=\frac{1}{x^{2}-1}-\frac{1}{x^{2}-3}$
8. $\sqrt{\frac{1+2x\sqrt{1-x^{2}}}{2}}=1-2x^{2}$
9. $x-1+\sqrt{x+1}+\sqrt{2-x}=x^{2}+\sqrt{2}$
10. $x^{4}+4x^{3}+5x^{2}+2x-10=12\sqrt{x^{2}+2x+5}$
11. $\sqrt{x}+\sqrt[4]{x(1-x)^{2}}+\sqrt[4]{(1-x)^{3}}=\sqrt{1-x}+\sqrt[4]{x^{3}}+\sqrt[4]{x^{2}(1-x)}$
12. $\sqrt[3]{12x^{2}+22x-49}-\sqrt[3]{x^{3}-3x^{2}-2x+5}=2x$
13. $\frac{6-2x}{\sqrt{5-x}}+\frac{6+2x}{\sqrt{5+x}}=\frac{8}{3}$
14. $x(2x+7)-4\sqrt{2x^{2}+9x+10}+10=(3x+2)(2\sqrt{x+2}-\sqrt{2x+5})$
15. $2.9^{x}+(4x-39-\sqrt{3^{x}+16}).3^{x}-(2x-13)(13+\sqrt{3^{x}+16})=0$
16. $\frac{\sqrt{x^{2}+x+2}}{1+\sqrt{2-x-x^{2}}}-\frac{\sqrt{x^{2}-x}}{1+\sqrt{4+x-x^{2}}}=x^{2}-1$
17. $\sqrt{\frac{x}{2}-\frac{22}{21}}-\sqrt[3]{x^{3}-3x^{2}+\frac{23}{7}}=1$
18. $1+\sqrt{1+8x^{2}-6x\sqrt{1-x^{2}}}=10x^{2}$
19. $\sqrt{x}-2\sqrt{5x-x^{2}-1+\sqrt{5-x}}=-2$
20. $\sqrt[3]{162x^{3}+2}-\sqrt{27x^{2}-9x+1}=1$
21. $\frac{\sqrt{4-x}}{1+\sqrt{x}}-\frac{\sqrt{3+x}}{1+\sqrt{1-x}}=2x-1$
22. $x-1+\sqrt[3]{\frac{7}{4}-x^{3}}=\sqrt{4x^{2}-4x-1}$
23. $3^{\sqrt{2x-2}+1}-3^{x}=x^{2}-4x+3$

anhxtanh2000 đã viết:Giải các phương trình sau:
1. $\sqrt{x+1}(3x^{2}+x+1)=x^{3}+3x^{2}+3x$